1/3z-1+1=6/3z^2-4z+1

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Solution for 1/3z-1+1=6/3z^2-4z+1 equation: 


z in (-oo:+oo)

(1/3)*z-1+1 = (6/3)*z^2-(4*z)+1 // - (6/3)*z^2-(4*z)+1

(1/3)*z-((6/3)*z^2)+4*z-1-1+1 = 0

(1/3)*z-2*z^2+4*z-1-1+1 = 0

13/3*z-2*z^2-1 = 0

DELTA = (13/3)^2-(-2*(-1)*4)

DELTA = 97/9

DELTA > 0

z = ((97/9)^(1/2)-13/3)/(-2*2) or z = (-(97/9)^(1/2)-13/3)/(-2*2)

z = ((97/9)^(1/2)-13/3)/(-4) or z = ((97/9)^(1/2)+13/3)/4

z in { ((97/9)^(1/2)-13/3)/(-4), ((97/9)^(1/2)+13/3)/4 }

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